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4x^2+73x+294=0
a = 4; b = 73; c = +294;
Δ = b2-4ac
Δ = 732-4·4·294
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-25}{2*4}=\frac{-98}{8} =-12+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+25}{2*4}=\frac{-48}{8} =-6 $
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